12b^2+13bc-35c^2=

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Solution for 12b^2+13bc-35c^2= equation:


Simplifying
12b2 + 13bc + -35c2 = 0

Reorder the terms:
13bc + 12b2 + -35c2 = 0

Solving
13bc + 12b2 + -35c2 = 0

Solving for variable 'b'.

Factor a trinomial.
(4b + -5c)(3b + 7c) = 0

Subproblem 1

Set the factor '(4b + -5c)' equal to zero and attempt to solve: Simplifying 4b + -5c = 0 Solving 4b + -5c = 0 Move all terms containing b to the left, all other terms to the right. Add '5c' to each side of the equation. 4b + -5c + 5c = 0 + 5c Combine like terms: -5c + 5c = 0 4b + 0 = 0 + 5c 4b = 0 + 5c Remove the zero: 4b = 5c Divide each side by '4'. b = 1.25c Simplifying b = 1.25c

Subproblem 2

Set the factor '(3b + 7c)' equal to zero and attempt to solve: Simplifying 3b + 7c = 0 Solving 3b + 7c = 0 Move all terms containing b to the left, all other terms to the right. Add '-7c' to each side of the equation. 3b + 7c + -7c = 0 + -7c Combine like terms: 7c + -7c = 0 3b + 0 = 0 + -7c 3b = 0 + -7c Remove the zero: 3b = -7c Divide each side by '3'. b = -2.333333333c Simplifying b = -2.333333333c

Solution

b = {1.25c, -2.333333333c}

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